The correct point-slope equation for the line that passes through the point (2, -5) and is parallel to the line given by y=-4x+25 is OB. y-5=-4(x+2).
To find the equation of a line that is parallel to another line, you need to use the fact that parallel lines have the same slope. The slope of the line y=-4x+25 is -4, so the slope of the new line must also be -4.
Using the point-slope form of a linear equation, we have:
y - y1 = m(x - x1)
where m is the slope of the line and (x1, y1) is a point on the line. Plugging in the values we have:
y - (-5) = -4(x - 2)
Simplifying:
y + 5 = -4x + 8
y - 4x = 3
Rearranging:
y - 4x - 3 = 0
So the equation of the line is y-5=-4(x+2).