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g iodine-131 decays by electron emission into xenon-131 with a half life of 8 days. a 1.000 gram sample of pure i-131 is produced (somehow!) at t

User AechoLiu
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Answer: The decay of iodine-131 into xenon-131 can be represented by the following nuclear equation:

^131I -> ^131Xe + e-

Given that the half-life of iodine-131 is 8 days, we can use the following equation to determine the amount of iodine-131 remaining after a certain time (t):

N = N0 * (1/2)^(t/T1/2)

where N is the amount of iodine-131 at time t, N0 is the initial amount of iodine-131 (1.000 g in this case), and T1/2 is the half-life of iodine-131 (8 days).

a) After 16 days:

Using the equation above, we can calculate the amount of iodine-131 remaining after 16 days:

N = 1.000 g * (1/2)^(16/8) = 0.500 g

Therefore, the amount of iodine-131 remaining after 16 days is 0.500 g.

b) After 24 days:

Using the same equation, we can calculate the amount of iodine-131 remaining after 24 days:

N = 1.000 g * (1/2)^(24/8) = 0.250 g

Therefore, the amount of iodine-131 remaining after 24 days is 0.250 g.

c) The time required for 99.9% of the iodine-131 to decay:

We can use the same equation to determine the time required for 99.9% of the iodine-131 to decay. We can set N/N0 equal to 0.001 (since we want to know when only 0.1% of the original amount remains):

0.001 = (1/2)^(t/8)

Taking the natural logarithm of both sides:

ln(0.001) = (t/8) ln(1/2)

t = -8 ln(0.001) / ln(1/2)

t = 69.3 days (approx.)

Therefore, the time required for 99.9% of the iodine-131 to decay is approximately 69.3 days.

User Gonzalo Hernandez
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