Question

Write the equation in standard form for the circle with center (-10, 0) passing through

(-12,3/2)

Answer 1

Explanation:

the standard equation for the circle is:

(x-a)²+(y-b)² = r²

the center is : A(a,b) and ridus r

you have : a= -10 and b=0 r²= (-12+10)²+(3/2-0)²= 4+ 9/4

r² = 25/4 so : r = 5/2

the standard equation for the circle is:

(x+10)²+y² =25/4