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How many mL of 12.0 M (molarity) of hydrochloric aqueous solution would be used to prepare 500.0 mL of a 0.100 M diluted solution?

User Naysa
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1 Answer

5 votes

We can use the formula:

M1V1 = M2V2

where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

In this case, we know:

M1 = 12.0 M

V1 = ?

M2 = 0.100 M

V2 = 500.0 mL = 0.500 L (since 1 mL = 0.001 L)

We can rearrange the formula to solve for V1:

V1 = (M2V2) / M1

Substituting the values we know, we get:

V1 = (0.100 M)(0.500 L) / 12.0 M

V1 = 0.00417 L = 4.17 mL

Therefore, we need to measure 4.17 mL of 12.0 M hydrochloric aqueous solution and add it to 500.0 mL of water to prepare 500.0 mL of a 0.100 M diluted solution.

User Rantao
by
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