Question

Express your answer as a polynomial in standard form (answer quickly)

f(x) = -2 + 1
g(x) = x^2 + x + 13

find g(f(x))

Answer 1

g(f(x)) = 4x²-6x+15

Explanation:

f(x) = -2x + 1

g(x) = x² + x + 13

To find g(f(x)), we sub f(x) for every x in g(x):

g(x) = x² + x + 13

g(f(x)) = (f(x))² + (f(x)) + 13

g(f(x)) = (-2x+1)² + (-2x+1) + 13

g(f(x)) = -2x(-2x+1)-2x+1-2x+14

g(f(x)) = 4x²-2x-4x+15

g(f(x)) = 4x²-6x+15

Answer 2

Answer: Hope this helps ;) don't forget to rate this answer !

Explanation:

To find g(f(x)), we need to substitute the expression for f(x) into the expression for g(x). The expression for f(x) is given as:

f(x) = -2 + 1

Substituting this expression into the expression for g(x), we get:

g(f(x)) = g(-2 + 1)

Since g(x) = x^2 + x + 13, we can substitute -2 + 1 for x to get:

g(f(x)) = (-2 + 1)^2 + (-2 + 1) + 13

Simplifying this expression gives:

g(f(x)) = (-1)^2 + (-1) + 13

= 1 - 1 + 13

= 13

Thus, the expression for g(f(x)) is 13. This is a polynomial in standard form.