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Write a sine function that has an amplitude of 3, a midline of y=2, and a period of 8π/7.​

User Rosalind
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2 Answers

5 votes

Answer:

Explanation:

User Alexander Suraphel
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Answer: The general form of a sine function is:

y = A sin (Bx + C) + D

Where:

A = amplitude

B = 2π/period

C = phase shift

D = vertical shift or midline

Given the values in the problem, we can substitute and simplify:

A = 3

midline = 2, so D = 2

period = 8π/7, so B = 2π/(8π/7) = 7/4

y = 3 sin (7/4 x + C) + 2

To find the phase shift, we need to use the fact that the sine function is at its maximum when the argument of the sine function is equal to π/2. That is:

Bx + C = π/2

We can solve for C:

C = π/2 - Bx

C = π/2 - (7/4) x

Substituting back the value of C in the equation, we get:

y = 3 sin (7/4 x + π/2 - 7/4 x) + 2

y = 3 sin (7/4 x - 7π/8) + 2

Therefore, the sine function with an amplitude of 3, a midline of y=2, and a period of 8π/7 is:

y = 3 sin (7/4 x - 7π/8) + 2

User Rickardo
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