Question

Enter the equation of the circle described below. Center (-1, 0), radius = sqrt 3

Answer 1

(x + 1)² + y² = 3

Explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

here (h, k ) = (- 1, 0 ) and r =
`√(3)` , then

(x - (- 1) )² + (y - 0)² = (
`√(3)` )² , that is

(x + 1)² + y² = 3