Question

Solve the system of linear equations by substitution. 3x-4y=12 x=-2y+4

Answer 1

Explanation:

if x=-2y+4

3x-4y=12 becomes

3(-2y+4)-4y=12

-6y+12-4y=12

-10y+12=12

-10y=0

y=0

since x=-2y+4

x=-2(0)+4

x=4

so the solution is the point (4,0)

Answer 2

x=4, y=0. (4, 0).

Explanation:

3x-4y=12

x=-2y+4

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3(-2y+4)-4y=12

-6y+12-4y=12

-10y=12-12

-10y=0

y=0/-10=0

x=-2(0)+4=0+4=4