Question

Use the graph to solve x^2+8x+16=0. Select all solutions that apply.

Answer 1

We can see from the graph that the parabola intersects the x-axis at -4 (where the vertex touches the x-axis).

Since the equation is in the form of ax^2 + bx + c = 0, we can identify that a = 1, b = 8, and c = 16.

Using the quadratic formula, we get:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

x = (-8 ± sqrt(8^2 - 4(1)(16))) / 2(1)

x = (-8 ± sqrt(0)) / 2

x = -4

Therefore, the only solution is x = -4.