Question

A long wire parallel to the x axis carries a current of 6.9 a in the positive x direction. there is a uniform magnetic field of 1.3 t in the y direction. find the magnitude of the force per unit

Answer 1

The magnitude of the force per unit length on a long wire carrying a current in a uniform magnetic field can be calculated using the formula F = I * B * L * sin(θ). In this case, the wire is parallel to the x-axis, carrying a current of 6.9 A in the positive x direction. The magnetic field is 1.3 T in the y direction. Therefore, the magnitude of the force per unit length is 8.97 N/m.

Step-by-step explanation:

The magnitude of the force per unit length on a long wire carrying a current in a uniform magnetic field can be calculated using the formula:

F = I * B * L * sin(θ)

Where F is the force per unit length, I is the current, B is the magnetic field, L is the length of the wire, and θ is the angle between the current direction and the magnetic field direction.

In this case, the wire is parallel to the x-axis, carrying a current of 6.9 A in the positive x direction. The magnetic field is 1.3 T in the y direction. Since the wire is parallel to the magnetic field, the angle between them is 90 degrees. Therefore, the magnitude of the force per unit length is:

F = 6.9 A * 1.3 T * 1 m = 8.97 N/m

Answer 2

The magnitude of the force per unit length on a wire carrying a current of 6.9 A in the presence of a uniform 1.3 T magnetic field in the y-direction is 8.97 N/m.

Step-by-step explanation:

The student asked to find the magnitude of the force per unit length acting on a current-carrying wire that is placed in a uniform magnetic field. This topic falls within the domain of physics, specifically involving concepts such as electromagnetism and the Lorentz force. To determine the force per unit length, one would use the equation F = I×L×B×sin(θ), where F is the force on the wire, I is the current through the wire, L is the length of the wire within the magnetic field, B is the magnetic field strength, and θ is the angle between the direction of the current and the magnetic field. However, since the question requires the force per unit length, the equation simplifies to f = I×B×sin(θ).

Given that the current I is 6.9 A, the magnetic field B is 1.3 T, and the angle θ is 90 degrees (current in the x-direction and magnetic field in the y-direction are perpendicular), the sin(θ) equals to 1. Plugging these values into the equation, we get:

f = 6.9 A × 1.3 T × 1

So, the magnitude of the force per unit length on the wire is 8.97 N/m.