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find an equation to calculate the value for rl that will reduce the power dissipated to the half of maximum power for the same circuit. how many possible solutions are there for this rl?

User Pudepied
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15 votes

Answer:

Find the RL value for the below circuit that the power is highest as well, find the highest power through RL using the theorem of maximum power transfer. According to this theorem, when power is highest via the load, then resistance is similar to the equal resistance between the two ends of the RL after eliminating it.

So, differentiate Equation 1 with respect to RL and make it equal to zero. Therefore, the condition for maximum power dissipation across the load is R L = R T h. That means, if the value of load resistance is equal to the value of source resistance i.e., Thevenin’s resistance, then the power dissipated across the load will be of maximum value.

The value of R so that the load of 20Ω should draw maximum power. The value of maximum power drawn by the load. Here, load given is of 20Ω. From maximum power transfer theorem, maximum power will be delivered to the load when the load resistance is equal to the internal resistance of the source (R­int = RTh).

As per maximum power transfer theorem, rL should be equal to the internal resistance of the network looking through x-y. Let this be Rint. To find Rint, all the sources are deactivated figure 11. Thus, the load resistance (rL) must be having a value of such that maximum power transfer is possible.

Step-by-step explanation:

User Pini
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