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find the magnitude, fh , of the force required to slide the lawnmower over the ground at constant speed by pushing the handle.

User Karloss
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1 Answer

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Answer:

fh = µkFn = µk(mg) = (0.2)(350 N) = 70 N

Step-by-step explanation:

The magnitude of the force required to slide the lawnmower over the ground at constant speed by pushing the handle is given by the formula fh = µkFn, where µk is the coefficient of kinetic friction, Fn is the normal force, and mg is the weight of the lawnmower. In this case, µk = 0.2, Fn = mg = (35 kg)(9.8 m/s^2) = 343 N, and thus fh = µkFn = (0.2)(343 N) = 68.6 N. Therefore, the magnitude of the force required to slide the lawnmower over the ground at constant speed by pushing the handle is 70 N (rounded to the nearest whole number).

User TryinHard
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