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1 vote
Solve for missing sides:
b
60°
a
5√3

Solve for missing sides: b 60° a 5√3-example-1

1 Answer

1 vote

Answer:

b = 5, a = 10.

Explanation:

sin 60 = 5√3 / a

√3/2 = 5√3 / a

a = 5√3 / √3/2

= 5√3 * 2/ √3

= 10

By pythagoras:

10^2 = (5√3)^ 2 + b^2

100 = 75 + b^2

b^2 = 25

b = 5

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