Final answer:
To balance the equation SO3²- + Cu(OH)2 -> SO42- + Cu(OH) in basic conditions, we need to balance the charges and atoms on both sides of the equation. Start by balancing the sulfur (S) atoms by adding a coefficient of 2 in front of the Cu(OH)2 on the reactant side. Next, balance the oxygen (O) atoms by adding water molecules (H2O) to the reactant side. Finally, balance the hydrogen (H) atoms by adding hydroxide ions (OH-) to the product side.
Step-by-step explanation:
To balance the equation
SO3²- (aq) + Cu(OH)2 (s) --> SO42- (aq) + Cu(OH)(s) In basic conditions, we need to balance the charges and atoms on both sides of the equation. We start by balancing the sulfur (S) atoms by adding a coefficient of 2 in front of the Cu(OH)2 on the reactant side, resulting in:
2SO3²- (aq) + Cu(OH)2 (s) --> SO42- (aq) + Cu(OH)(s)
Next, we balance the oxygen (O) atoms by adding water molecules (H2O) to the reactant side:
2SO3²- (aq) + Cu(OH)2 (s) + 3H2O (l) --> SO42- (aq) + Cu(OH)(s)
Finally, we balance the hydrogen (H) atoms by adding hydroxide ions (OH-) to the product side:
2SO3²- (aq) + Cu(OH)2 (s) + 3H2O (l) --> SO42- (aq) + Cu(OH)(s) + 6OH- (aq)