Question

Balance the following equation in basic conditions. Phases are optional. SO3^2- + Co(OH)2 ---> Co + SO4^2-

Answer 1

To balance the equation SO3²- + Co(OH)2 ---> Co + SO4²- in basic conditions, separate the species into their ionic forms, balance the charge and the atoms, and cancel out all spectator ions. The balanced equation in basic conditions is 3SO3²- + 2Co(OH)2 ---> 2Co + 3SO4²- + 3H2O.

Step-by-step explanation:

To balance the equation SO3²- + Co(OH)2 ---> Co + SO4²- in basic conditions, you need to follow the steps:

After following these steps, the balanced equation in basic conditions would be 3SO3^2- + 2Co(OH)2 ---> 2Co + 3SO4²- + 3H2O.

Answer 2

To balance the equation SO3²- + Cu(OH)2 -> SO42- + Cu(OH) in basic conditions, we need to balance the charges and atoms on both sides of the equation. Start by balancing the sulfur (S) atoms by adding a coefficient of 2 in front of the Cu(OH)2 on the reactant side. Next, balance the oxygen (O) atoms by adding water molecules (H2O) to the reactant side. Finally, balance the hydrogen (H) atoms by adding hydroxide ions (OH-) to the product side.

Step-by-step explanation:

To balance the equation
SO3²- (aq) + Cu(OH)2 (s) --> SO42- (aq) + Cu(OH)(s) In basic conditions, we need to balance the charges and atoms on both sides of the equation. We start by balancing the sulfur (S) atoms by adding a coefficient of 2 in front of the Cu(OH)2 on the reactant side, resulting in:

2SO3²- (aq) + Cu(OH)2 (s) --> SO42- (aq) + Cu(OH)(s)

Next, we balance the oxygen (O) atoms by adding water molecules (H2O) to the reactant side:

2SO3²- (aq) + Cu(OH)2 (s) + 3H2O (l) --> SO42- (aq) + Cu(OH)(s)

Finally, we balance the hydrogen (H) atoms by adding hydroxide ions (OH-) to the product side:

2SO3²- (aq) + Cu(OH)2 (s) + 3H2O (l) --> SO42- (aq) + Cu(OH)(s) + 6OH- (aq)