Question

Calculate the power being dissipated by the third resistor p3, in watts.

Answer 1

The power being dissipated by the third resistor, P3, is 4.50 watts.

Step-by-step explanation:

In order to calculate the power being dissipated by the third resistor, we can use the equation P₁ + P₂ + P₃ = 18.00 W, where P₁, P₂, and P₃ are the powers dissipated by the first, second, and third resistors respectively. We know that P₁ and P₂ are 9.00 W and 4.50 W respectively, so to find P₃, we can substitute these values into the equation:

P₃ = 18.00 W - 9.00 W - 4.50 W = 4.50 W.

Therefore, the power being dissipated by the third resistor is 4.50 watts.

Answer 2

The power dissipated by the third resistor, P3, in physics, relates to the electric power dissipated in a circuit as per Joule's law. Without specific current or voltage values, we cannot calculate P3 but can confirm that the total power dissipated equals the power output of the source, adhering to energy conservation.

Step-by-step explanation:

Calculating the power being dissipated by the third resistor, P3, is an application of the principles of electricity and energy conservation. The power dissipated by a resistor in a DC circuit can often be calculated using Joule's law, which states that P = IV, where P is the electric power, I is the current, and V is the voltage across the resistor.

From the provided information, it appears that the third resistor, P3, has been found through different calculations or setups in the described module. Since the exact values for current or voltage specific to P3 are not given in the information, we cannot provide a specific calculation for P3 without additional context. However, the sums provided (e.g., 7.20 W and 179 W) imply that in each case, the total power supplied by the source is equal to the sum of the powers dissipated by all the resistors, as expected from the law of conservation of energy.