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Consuela is displaying a cylindrical case on a pedestal. She wants it to be placed so that there is an even amount of space on either side of the case. If the volume of the cylinder shown is 1,130.97 cubic inches, how much space will be on either side if it’s placed on a pedestal that is 18 inches across? Round to the nearest inch.

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Answer:

First, we need to find the radius of the cylinder. We know that:

V = πr^2h

And we are given that V = 1,130.97 cubic inches. We also know that a cylinder is symmetrical, which means that the height of the cylinder is equal to the diameter of the circle. In other words, h = 2r.

Therefore, we can rewrite the formula as:

V = πr^2(2r)

1,130.97 = πr^3

r^3 = 359.82

r = 7.12 inches (rounded to two decimal places)

Now we need to find the amount of space on either side of the cylinder. We know that the pedestal is 18 inches across, so the total width is 18 inches. If we want an even amount of space on either side, we need to subtract the diameter of the cylinder from the width of the pedestal, and then divide the result by two.

Diameter = 2r = 2(7.12) = 14.24 inches

Space on either side = (18 - 14.24)/2 = 1.88 inches (rounded to two decimal places)

Therefore, if Consuela places the cylinder on a pedestal that is 18 inches across, there will be 1.88 inches of space on either side.

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