Question

The vertex form of the equation iof a aprabola is y=(x-4)^2+22

Answer 1

The answer to your problem is, y = x^2 - 8x + 38

Explanation:

Here is the vertex form of the equation:

y = (x - 4)^2 + 22

Then expand it for easier notice:

y = x^2 - 8x + 16 + 22

Evaluate:

y = x^2 - 8x + 38

Thus the answer to your problem is, y = x^2 - 8x + 38