Question

Calculate the mass defect of the fluorine nucleus 199F. The mass of neutral 199F is equal to 18.998403 atomic mass units. Express your answer in atomic mass units to four significant figures.

Answer 1

The mass defect of the fluorine nucleus 199F is approximately -9.9147 atomic mass units.

Step-by-step explanation:

The mass defect of the fluorine nucleus 199F can be calculated by subtracting the observed mass of a neutral 199F atom from the sum of the masses of its protons, neutrons, and electrons. The observed mass of 199F is 18.998403 atomic mass units. The mass of a proton is approximately 1.0073 atomic mass units, the mass of a neutron is approximately 1.0087 atomic mass units, and the mass of an electron is very small compared to protons and neutrons, so it can be neglected in this calculation.

Therefore, the mass defect of the fluorine nucleus 199F is:

Mass defect = [(9 x 1.0073 amu) + (10 x 1.0087 amu)] - 18.998403 amu

Mass defect = 9.0837 amu - 18.998403 amu = -9.914703 amu

So, the mass defect of the fluorine nucleus 199F is approximately -9.9147 atomic mass units.

Answer 2

The mass defect of the Fluorine is determined as 0.0016 amu.

How to calculate the mass defect of the Fluorine?

The mass defect of the Fluorine is calculated as follows;

Δm = m₁ - m₀

where;

• m₁ is the atomic mass of the Fluorine
• m₀ is the mass of neutral 199F

The given parameters include;

the atomic mass of Fluorine = 19 amu

mass of neutral 199F = 18.998403 amu

The mass defect of the Fluorine is calculated as follows;

Δm = 19 amu - 18.998403 amu

Δm = 0.001597 amu

Δm = 0.0016 amu (four significant figures)

Thus, the mass defect of the Fluorine is determined as 0.0016 amu.