Question

If there are 7.00 moles of Al(OH)3, how many grams of Ca(OH)2 will be formed?

3CaCl2 + 2Al(OH)3 = 3Ca(OH)2 + 2AlCl3

Answer 1

Answer: Mass of Ca(OH)2 formed will be 777g.

Step-by-step explanation:

As from the reaction we can see,

2 moles of Al(OH)3 gives 3 moles of Ca(OH)2.

1 mole of Al(OH)3 gives 3/2 moles of Ca(OH)2.

7 moles of Al(OH)3 gives ((3/2)x 7) moles of Ca(OH)2.

7 moles of Al(OH)3 gives (21/2) moles of Ca(OH)2.

So, no. of moles of Ca(OH)2= 21/2 mole

Molar mass of Ca(OH)2 = 74 g/mole

Mass of Ca(OH)2 = No. of moles x Molar mass

= (21/2) x 74

= 777g