Answer:
Explanation:
To find how far David is from his starting point, we can use the Pythagorean theorem, which states that for a right triangle, the sum of the squares of the lengths of the legs (the two shorter sides) is equal to the square of the length of the hypotenuse (the longest side).
In this case, David's path forms a right triangle with sides of 200 meters (west) and 125 meters (north). The distance he is from his starting point is the length of the hypotenuse.
Using the Pythagorean theorem:
c^2 = a^2 + b^2
where c is the length of the hypotenuse and a and b are the lengths of the legs.
c^2 = 200^2 + 125^2
c^2 = 40000 + 15625
c^2 = 55625
Taking the square root of both sides:
c = sqrt(55625)
c ≈ 236.05
Therefore, David is approximately 236 meters from his starting point. Rounded to the nearest whole meter, he is 236 meters away.