Question

NEED HELP ASAP

8. Write the standard equation for the circle center (-6,7), r-9. (1 point)
(x-6)²+(y+7)² =9
o(x-7)² + (x+6)²=81
○ (x+6)² + (y-7)² = 81
○(x+6)²+(y-7)² =9


9. Write the standard equation for the circle center (-6,-8), that passes through (0,0). (1 point)
o(x-6)²+(y-8)² =10
o(x-6)²+(-8)² = 196
O(x+6)²+(y+8)²-14
o(x+6)²+(y+8)² = 100

Answer 1

Answer:

The standard equation for a circle with center (h,k) and radius r is (x-h)² + (y-k)² = r².

For question 9, the given information is the center (-6,-8) and the point (0,0) that passes through the circle. We can use the distance formula to find the radius:

r = √[(0-(-6))² + (0-(-8))²]

r = √[6² + 8²]

r = √100

r = 10

Now we can use the standard equation:

(x-h)² + (y-k)² = r²

(x-(-6))² + (y-(-8))² = 10²

(x+6)² + (y+8)² = 100

Therefore, the correct answer is (o) (x+6)² + (y+8)² = 100.

Answer 2

8. (x+6)² + (y-7)² = 81

9. (x+6)² + (y+8)² = 100

Explanation: