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Using a ruler and a pair of compass only, construct a triangle ABC with |BC|= 9cm , |AC|=8cm and |AC|=6cm. Construct a perpendicular bisector of line BC. Construct the bisector of angle ABC. ​

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1. Draw a line segment BC of length 9cm.

2. From point B, draw a circle with a radius of 6cm.

3. From point C, draw a circle with a radius of 8cm.

4. Label the points of intersection of the two circles as A and A'.

5. Draw a line segment AA'.

6. Draw a perpendicular bisector of line segment BC. To do this, draw a circle with center B and radius greater than half of BC. Draw another circle with center C and the same radius. Let the two circles intersect at points P and Q. Draw a line through P and Q. This line is the perpendicular bisector of BC.

7. Label the point of intersection of the perpendicular bisector and line segment BC as D.

8. Draw the bisector of angle ABC. To do this, draw a circle with center A and radius greater than AB. Let the circle intersect AB and AC at points E and F respectively. Draw a line through B and F. This line is the bisector of angle ABC.

9. Label the point of intersection of the angle bisector and line segment BC as G.
User Rohit Heera
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