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How do you factor 64-(x+4y)^2 completely
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How do you factor 64-(x+4y)^2 completely

User Pierangelo Orizio
by
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1 Answer

2 votes

Answer:

64-(x+4y)^2=(8)^2-(x+4y)^2=(8+x+4y)(8-x-4y)

Explanation:

can use

a^2-b^2=(a+b)(a-b)

User Olle
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