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A pair of dice are tossed twice what is the probability that the first roll is a total of at least 6 and the second roll is a total of at least 8

User Bmbariah
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Answer: 65/216

65/216 = 0.3009 = 30.09% approximately

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Step-by-step explanation:

Refer to the sum of dice chart shown below.

That table shows all 36 possible sums when rolling two dice. Each has 6 sides labeled "1" through "6".

Use that chart to find that there are 10 ways to get a sum of 2, 3, 4 or 5.

That must mean there are 36-10 = 26 ways to get a sum of 6 or larger.

A = 26/36 = 13/18 is the probability of getting a sum of 6 or larger.

Use the table to find there are 15 ways to get a sum of 8 or larger.

B = 15/36 = 5/12 is the probability of getting a sum of 8 or larger.

Then we multiply those fractions.

A*B = (13/18)*(5/12) = (13*5)/(18*12) = 65/216

That fraction cannot be reduced further because 65 and 216 have no common factors other than 1.

65/216 = 0.3009 = 30.09% approximately

A pair of dice are tossed twice what is the probability that the first roll is a total-example-1
User Designer
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