Answer: 270
Step-by-step explanation: a. When x = 5 and y = 7,
x'y' = 5'7'
= 10110101 (in binary)
= 181 (in decimal)
b. x'y' can be written as (2^3+1)(2^2+1)(2^1+1)(2^0+1), where ^ denotes exponentiation.
c. When x = 5 and y = 7,
x'y' = (2^3+1)(2^2+1)(2^1+1)(2^0+1)
= (8+1)(4+1)(2+1)(1+1)
= 953*2
= 270
d. No, we did not get the same value for parts a and c. The reason for this is that in part a, we evaluated x'y' using binary arithmetic, while in part c, we evaluated it using decimal arithmetic. The two methods of arithmetic yield different results.