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2=x^2-10x
Find the zeros

User Tesfa
by
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1 Answer

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To find the zeros of the equation:

2 = x^2 - 10x

we first need to rearrange the equation into standard quadratic form:

x^2 - 10x - 2 = 0

Now we can use the quadratic formula to solve for x:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 1, b = -10, and c = -2.

Substituting these values, we get:

x = (-(-10) ± sqrt((-10)^2 - 4(1)(-2))) / 2(1)

Simplifying inside the square root:

x = (10 ± sqrt(100 + 8)) / 2

x = (10 ± sqrt(108)) / 2

x = (10 ± 6√3) / 2

x = 5 ± 3√3

Therefore, the zeros of the equation are:

x = 5 + 3√3 and x = 5 - 3√3

User Kenza
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