To find the zeros of the equation:
2 = x^2 - 10x
we first need to rearrange the equation into standard quadratic form:
x^2 - 10x - 2 = 0
Now we can use the quadratic formula to solve for x:
x = (-b ± sqrt(b^2 - 4ac)) / 2a
where a = 1, b = -10, and c = -2.
Substituting these values, we get:
x = (-(-10) ± sqrt((-10)^2 - 4(1)(-2))) / 2(1)
Simplifying inside the square root:
x = (10 ± sqrt(100 + 8)) / 2
x = (10 ± sqrt(108)) / 2
x = (10 ± 6√3) / 2
x = 5 ± 3√3
Therefore, the zeros of the equation are:
x = 5 + 3√3 and x = 5 - 3√3