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For the function -3x^2+12

find the interval over which the function is increasing.

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Answer:

The given function is:

f(x) = -3x^2 + 12

To find the interval over which the function is increasing, we need to find the critical points of the function.

f'(x) = -6x

The critical point is where f'(x) = 0

-6x = 0

x = 0

Now, we need to check the sign of f'(x) on either side of the critical point to determine whether the function is increasing or decreasing.

If x < 0, then f'(x) < 0, so the function is decreasing.

If x > 0, then f'(x) > 0, so the function is increasing.

Therefore, the interval over which the function is increasing is:

(0, infinity)

Explanation:

gg

User Dony
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