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For the function 8-(x-3)^2

find the coordinates of the vertex of its graph.

1 Answer

3 votes

The given function is in vertex form, which is:

f(x) = a(x - h)^2 + k

where (h, k) is the vertex of the parabola.

Comparing the given function to the vertex form, we can see that a = -1, h = 3, and k = 8.

Therefore, the vertex of the graph is at the point (h, k) = (3, 8).

So the coordinates of the vertex of the graph are (3, 8).

User Vincent Wen
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