Answer:
To find the coordinates of the vertex of the graph of the function -3x^2+12, we can use the formula x = -b/2a to find the x-coordinate of the vertex, and then substitute it back into the function to find the y-coordinate.
In this case, the function is in the form f(x) = -3x^2+12, so we can see that a = -3 and b = 0.
Using the formula x = -b/2a, we get:
x = -0/(2*(-3)) = 0
So the x-coordinate of the vertex is 0.
To find the y-coordinate of the vertex, we can substitute x = 0 into the function:
f(0) = -3(0)^2+12 = 12
So the y-coordinate of the vertex is 12.
Therefore, the coordinates of the vertex of the graph of the function -3x^2+12 are (0, 12).
Explanation:
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