Question

A call center claims that the mean wait time for a customer to connect with a customer care executive is at most 2 minutes. A random sample of 20 calls at the call center yielded a test statistic of 1.75. Assuming that the wait time is normally distributed, what is the corresponding p-value? Round your answer to three decimal places.

Answer 1

To find the p-value, we need to first find the corresponding area in the normal distribution table for the test statistic of 1.75.

Since the sample size (n) is greater than 30 and the population standard deviation is unknown, we use the t-distribution to calculate the p-value.

The degrees of freedom (df) for the t-distribution is n - 1 = 20 - 1 = 19.

Using a t-table or calculator, we can find that the area to the right of 1.75 (with df=19) is approximately 0.049.

Since this is a one-tailed test (the alternative hypothesis is that the mean wait time is greater than 2 minutes), the p-value is equal to the area to the right of the test statistic, which is 0.049.

Therefore, the corresponding p-value is 0.049 (rounded to three decimal places).

Explanation:

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