Question

What is the kinetic energy of 0.01 kg bullet traveling at a velocity of 700 m/s

Answer 1

2450J

Step-by-step explanation:

Acc to eq

K.E= 1/2mv^2

By putting values we get

K.E = 1/2(0.01kg)(700)^2

we get the answer:

2450J (joules?)