Question

Given that ka for hclo is 4.0×10−8 at 25 °c, what is the value of kb for clo− at 25 °c?

Answer 1

The value of Kb for ClO- at 25 °C is 2.5 × 10⁻7.

Step-by-step explanation:

To find the value of Kb for ClO- at 25 °C, we can use the relationship between Ka and Kb for a conjugate acid-base pair. Ka is the acid dissociation constant for HClO, which is the conjugate acid of ClO-.

The relationship between Ka and Kb is given by the equation Ka * Kb = Kw. Since we know that Ka = 4.0 × 10⁻8, we can rearrange the equation to solve for Kb: Kb = Kw / Ka.

Substituting the known values, we have Kb = (1.0 × 10⁻14) / (4.0 × 10⁻8) = 2.5 × 10⁻7.

Answer 2

The value of kb for ClO− at 25 °C is calculated using the relationship kb = kw / ka, and it is found to be 2.5×10−7.

Step-by-step explanation:

To determine the value of kb for ClO− at 25 °C, given that the ka for HClO is 4.0×10−8, we use the relationship between the ionization constant of an acid (ka) and the ionization constant of its conjugate base (kb). The product of ka and kb for a conjugate acid-base pair is equal to the ion product of water (kw), which at 25 °C is 1.0×10−14. Knowing this, we can calculate kb as follows:

kb = kw / ka

substitute given values:

kb = (1.0×10−14) / (4.0×10−8)

kb = 2.5×10−7

Hence, the value of kb for ClO− at 25 °C is 2.5×10−7.