Question

a sample of nitrogen gas exerted a pressure of 1 atmosphere when kept in a container of volume 300cm3 in a refrigerator at a temperature of 3C. the gas is transferred to a larger container and allowed to reach a temperature of 25C and a pressure of 0.8 atmosphere. what is the volume of the larger container

Answer 1

We can use the combined gas law to solve this problem:

(P1V1/T1) = (P2V2/T2)

where:

P1 = 1 atm (pressure of nitrogen gas in the first container)

V1 = 300 cm^3 (volume of the first container)

T1 = 3°C + 273.15 = 276.15 K (temperature of the nitrogen gas in the first container, converted to Kelvin)

P2 = 0.8 atm (pressure of nitrogen gas in the second container)

V2 = ? (volume of the second container, what we want to find)

T2 = 25°C + 273.15 = 298.15 K (temperature of the nitrogen gas in the second container, converted to Kelvin)

Plugging in the values, we get:

(1 atm x 300 cm^3) / 276.15 K = (0.8 atm x V2) / 298.15 K

Simplifying and solving for V2, we get:

V2 = (1 atm x 300 cm^3 x 298.15 K) / (0.8 atm x 276.15 K)

V2 = 1309.5 cm^3

Therefore, the volume of the larger container is approximately 1309.5 cm^3.