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115g of H2 reacts with 150g of O2. What is the theoretical Yield of water in grams

User Radlan
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Answer: The balanced chemical equation for the reaction between hydrogen and oxygen to form water is:

2H2 + O2 → 2H2O

From the equation, we can see that two moles of hydrogen react with one mole of oxygen to produce two moles of water. Therefore, the limiting reagent in this reaction is the one that will be completely consumed, which is either hydrogen or oxygen, depending on which one is present in smaller quantity.

To determine the limiting reagent, we need to calculate the number of moles of each reactant:

Number of moles of H2 = 115g / 2.016g/mol = 57.1 mol

Number of moles of O2 = 150g / 32.00g/mol = 4.69 mol

Since oxygen has fewer moles than hydrogen, it is the limiting reagent. Therefore, we can calculate the theoretical yield of water using the number of moles of oxygen:

Number of moles of H2O = 4.69 mol O2 × (2 mol H2O / 1 mol O2) = 9.38 mol H2O

Finally, we can convert the number of moles of water to grams using its molar mass:

Theoretical yield of water = 9.38 mol × 18.015 g/mol = 168.8 g

Therefore, the theoretical yield of water in grams is 168.8 g.

User Jo David
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