Question

Determine the energy, in J, of a photon with a wavelength of 377 nm.

(h= 6.626 x 1034 Js and c = 3.00 x 10 m/s)

Answer 1

Answer: the energy of a photon with a frequency of 377 nm is roughly 1.660 x 10^-19 J.

Step-by-step explanation:

E = hc/λ

where E is the energy of the photon, h is the Planck steady (6.626 x 10^-34 J s), c is the speed of light (2.998 x 10^8 m/s), and λ is the frequency of the photon.

To begin with, we want to change over the frequency of the photon from nanometers to meters:

377 nm = 377 x 10^-9 m

Presently, we can substitute the qualities into the situation:

E = (6.626 x 10^-34 J s)(2.998 x 10^8 m/s)/(377 x 10^-9 m)

Improving on the situation:

E = 1.660 x 10^-19 J