Answer: the energy of a photon with a frequency of 377 nm is roughly 1.660 x 10^-19 J.
Step-by-step explanation:
E = hc/λ
where E is the energy of the photon, h is the Planck steady (6.626 x 10^-34 J s), c is the speed of light (2.998 x 10^8 m/s), and λ is the frequency of the photon.
To begin with, we want to change over the frequency of the photon from nanometers to meters:
377 nm = 377 x 10^-9 m
Presently, we can substitute the qualities into the situation:
E = (6.626 x 10^-34 J s)(2.998 x 10^8 m/s)/(377 x 10^-9 m)
Improving on the situation:
E = 1.660 x 10^-19 J