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How many moles of AgNO3 are needed to prepare 452 mL of a 2.3 M solution?

User Vasile Doe
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Answer: To determine the number of moles of AgNO3 needed to prepare a 2.3 M solution in 452 mL, we can use the formula:

moles = concentration (M) x volume (L)

First, we need to convert the volume from milliliters to liters by dividing by 1000:

452 mL ÷ 1000 mL/L = 0.452 L

Next, we can plug in the values we know:

moles = 2.3 M x 0.452 L

moles = 1.0416

Therefore, we need 1.0416 moles of AgNO3 to prepare a 2.3 M solution in 452 mL.

User Alexloh
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