Answer: To determine the number of moles of AgNO3 needed to prepare a 2.3 M solution in 452 mL, we can use the formula:
moles = concentration (M) x volume (L)
First, we need to convert the volume from milliliters to liters by dividing by 1000:
452 mL ÷ 1000 mL/L = 0.452 L
Next, we can plug in the values we know:
moles = 2.3 M x 0.452 L
moles = 1.0416
Therefore, we need 1.0416 moles of AgNO3 to prepare a 2.3 M solution in 452 mL.