Answer:
16
Explanation:
let the center be O then OB=12,OG=12
and ΔROG is right angle triangle at G
Applying Pythagoras' theorem in ΔROG,
RO=RB+BO=8+12=20
∴GR²+OG²=RO²
x²+12²=20²
x²=400-144
=256
x=√256
=16
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