Question

The gas in a 250.0 mL piston experiences a change in pressure from 1.25 atm to 2.00 atm. What is the new volume (in mL) assuming the moles of gas and temperature are held constant?

Answer 1

The new volume of the gas is 156.25 mL.

Step-by-step explanation:

According to Boyle's Law, at constant temperature and number of moles, the pressure and volume of a gas are inversely proportional.

So, we can use the following equation to solve for the new volume (V2):

P1V1 = P2V2

Where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume, respectively.

Substituting the given values:

(1.25 atm) x (250.0 mL) = (2.00 atm) x V2

Solving for V2:

V2 = (1.25 atm x 250.0 mL) / (2.00 atm)

V2 = 156.25 mL

Therefore, the new volume of the gas is 156.25 mL.