Question

A 25.0 l metal tank contains 12.0 moles of hydrogen gas and 4.0 moles of nitrogen gas at a temperature of 298 k. what is the pressure in the tank in atm?

Answer 1

To calculate the pressure in the tank in atm, we can use the ideal gas law equation:

PV = nRT

Where P is the pressure, V is the volume of the tank (25.0 L), n is the total number of moles of gas (12.0 + 4.0 = 16.0 mol), R is the universal gas constant (0.0821 L*atm/mol*K), and T is the temperature in Kelvin (298 K).

First, we need to calculate the total number of moles of gas per liter of the tank:

n/V = 16.0 mol / 25.0 L = 0.64 mol/L

Then we can plug in all the values into the ideal gas law equation and solve for P:

P = (n/V) * RT = (0.64 mol/L) * (0.0821 L*atm/mol*K) * (298 K) = 15.3 atm

Therefore, the pressure in the tank is 15.3 atm.