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An iron rod has a diameter of 3.5cm and a height of 5.5cm. if the mass of the rod is 41.82kg, find the density in g/cm3

User JasonD
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1 Answer

4 votes

Answer:

Explanation:

The volume of the iron rod can be calculated using the formula for the volume of a cylinder:

V = πr^2h

where r is the radius of the cylinder, which is half of the diameter. Therefore, the radius of the iron rod is 3.5/2 = 1.75 cm.

Substituting the given values, we get:

V = π(1.75)^2(5.5)

V = 68.728 cm^3

The density of the iron rod can be calculated using the formula:

density = mass / volume

Substituting the given values, we get:

density = 41.82 kg / 68.728 cm^3

We need to convert kg to g and cm^3 to cm^3, so we multiply by 1000/1 and 1/1, respectively:

density = (41.82 kg / 68.728 cm^3) x (1000 g / 1 kg) x (1 cm^3 / 1 cm^3)

density = 610.34 g/cm^3

Therefore, the density of the iron rod is 610.34 g/cm^3 (to two decimal places).

User Jthetzel
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