Answer:
Explanation:
The volume of the iron rod can be calculated using the formula for the volume of a cylinder:
V = πr^2h
where r is the radius of the cylinder, which is half of the diameter. Therefore, the radius of the iron rod is 3.5/2 = 1.75 cm.
Substituting the given values, we get:
V = π(1.75)^2(5.5)
V = 68.728 cm^3
The density of the iron rod can be calculated using the formula:
density = mass / volume
Substituting the given values, we get:
density = 41.82 kg / 68.728 cm^3
We need to convert kg to g and cm^3 to cm^3, so we multiply by 1000/1 and 1/1, respectively:
density = (41.82 kg / 68.728 cm^3) x (1000 g / 1 kg) x (1 cm^3 / 1 cm^3)
density = 610.34 g/cm^3
Therefore, the density of the iron rod is 610.34 g/cm^3 (to two decimal places).