Answer:
Explanation:
Brahmagupta's solution to a quadratic equation of the form ax² + bx = c is given by x = (-b ± √(b² - 4ac)) / 2a.
For the equation 3x² + 4x = 6, we have a = 3, b = 4, and c = 6. Plugging these values into the formula, we get:
x = (-4 ± √(4² - 4(3)(6))) / 2(3)
x = (-4 ± √(16 - 72)) / 6
x = (-4 ± √(-56)) / 6
Since the square root of a negative number is not a real number, the quadratic equation has no real solutions. Therefore, Brahmagupta would not have found a solution for this particular equation using his method.