Hi gautamshubhi98, it is my pleasure to assist you in answering this question in-depth step by step today.
Okay, to determine the values that relate Revenue (X) and Salvage (Y) for the project to be feasible, we can use the annual worth analysis equation:
AW = P(A/P, i, n) - X(A/F, i, n) - Y
Where:
P = initial cost = $80,000
A = annual revenue = $15,000
X = revenue factor
Y = salvage value factor
i = MARR = 12% per year
n = project life = 7 years
Substituting the values into the equation, we get:
AW = 80,000(A/P, 12%, 7) - X(A/F, 12%, 7) - Y
To find the values of X and Y, we need to set the equation equal to zero (since the project is feasible when the annual worth is zero):
0 = 80,000(A/P, 12%, 7) - X(A/F, 12%, 7) - Y
Solving for X, we get:
X = 80,000(A/P, 12%, 7) - Y / (A/F, 12%, 7)
Substituting the values into the equation, we get:
X = 12,879.77 - 1,289.55Y
Therefore, the values that relate Revenue (X) and Salvage (Y) for the project to be feasible are:
X <= 12,879.77 - 1,289.55Y
To create a two-factor sensitivity graph, we can plot Revenue (X) on the y-axis and Salvage (Y) on the x-axis. The equation X = 12,879.77 - 1,289.55Y represents the boundary between the favorable and unfavorable regions. The 15% error region can be represented by a box centered at the point (2,500, 15,000) with a width of 2,500 and a height of 3,750 (15,000 x 0.15 = 2,250, which we round up to 2,500 for simplicity).