Question

The bar graph shows the number of Asturian households, in thousands, living in poverty from 1999 to 2004. The table holds a quadratic function for the data, where y is the number of households, in thousand living in poverty × years after 1999. 10. 10 1999 2000 2001 2002 2003 2004 QuadReg y = ax2 + bx + c a = 0.2299729818 b = - 0.4599459636 c = 7.5426446323 a. Use the table to express the model in function notation, with numbers rounded to two decimal places #(x) = 0.23x2 + - 0.46x + 7.54 b. According to the function in part (a), in which year was the number of households living in poverty at a minimum? 2000 (Round to the nearest year as needed.) c. Use the model to find the number of households, in thousands, for that year. 7400 (Round to one decimal place as needed.)

Answer 1

Explanation:

a. #(x) = 0.23x^2 - 0.46x + 7.54 (numbers rounded to two decimal places)

b. To find the year at which the number of households living in poverty is at a minimum, we need to find the vertex of the quadratic function. The x-value of the vertex is given by -b/2a. Plugging in the values for a and b from the function in part (a), we get:

x = -(-0.46)/(2*0.23) = 1

So the minimum occurs in the year 1999 + 1 = 2000 (rounded to the nearest year).

c. To find the number of households living in poverty in 2000, we need to evaluate the function at x = 1 (since 2000 is 1 year after 1999). Plugging in x = 1 into the function from part (a), we get:

#(1) = 0.23(1)^2 - 0.46(1) + 7.54 = 7.40

So there were approximately 7400 households living in poverty in Asturias in 2000 (rounded to one decimal place).