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Solving Quadratic Equations with the Quadratic Formula
Which equation has the components of 0=x²-9x-20 inserted into the quadratic formula correctly?
Ox= -9+√(- 9)² - 4(1)(-20)
2(1)
Ox= 9+√(-9)²-4(1)(20)
2(1)
O x= 9±√(-9)² - 4(1)(-20)
2(1)
O x = −9+√√(-9)² +4(1)(-20)
2(1)
Done

Answer 1

Explanation:

The equation that has the components of 0=x²-9x-20 inserted correctly into the quadratic formula is:

x= (-(-9) ± √((-9)² - 4(1)(-20))) / 2(1)

This is because the quadratic formula states that for an equation in the form ax² + bx + c = 0, the solutions for x are given by x = (-b ± sqrt(b² - 4ac)) / 2a. In this case, a = 1, b = -9, and c = -20. Therefore, the correct way to insert these components into the quadratic formula is as shown above. The other equations provided either have incorrect operations (such as squaring a negative value), or square-rooting a value that should not be square-rooted, resulting in an incorrect answer.

I hope this help.

Answer 2

Answer: C

Explanation:

A is not right they didn't take the opposite sign at the very beginning

B is wrong, should be -20 not 20

C is right

D is wrong because it should be +9 not -9