Question

A group project last semester looked to see how many services students knew about on campus. They collected data from 50 students and found that 23 had used tutoring and found it beneficial. Calculate a 95% confidence interval for the true proportion of Mesa students that have used tutoring and found it beneficial.

Answer 1

To calculate the confidence interval, we'll use the formula:

CI = sample proportion ± z* (standard error)

where:

- sample proportion = p_hat = 23/50 = 0.46 (proportion of students in the sample who used tutoring and found it beneficial)

- z = 1.96 (for a 95% confidence level)

- standard error = sqrt(p_hat * (1 - p_hat) / n) = sqrt(0.46 * 0.54 / 50) = 0.101

Plugging these values into the formula, we get:

CI = 0.46 ± 1.96 * 0.101

CI = [0.263, 0.657]

Therefore, we can say with 95% confidence that the true proportion of Mesa students who have used tutoring and found it beneficial is between 0.263 and 0.657.