Question

When a flare is shot upward with a velocity of 90 feet per second, its height, h, in feet, above the ground at t seconds

can be found by the function h(t)= - 16t² + 90t.
a) Find the height of the flare 2 seconds after it was shot.
b) Express the function with the right side in factored form.
c) Evaluate h(2) using the factored form from part b).

Answer 1

a) To find the height of the flare 2 seconds after it was shot, we can substitute t=2 into the function h(t):

h(2) = -16(2)² + 90(2) = -64 + 180 = 116

Therefore, the height of the flare 2 seconds after it was shot is 116 feet.

b) To express the function in factored form, we can factor out -16t from the right side:

h(t) = -16t(t - 5.625)

Therefore, the function in factored form is h(t) = -16t(t - 5.625).

c) To evaluate h(2) using the factored form from part b), we can substitute t=2 into the factored form:

h(2) = -16(2)(2 - 5.625) = -16(-3.625) = 58

Therefore, h(2) = 58 when using the factored form of the function.

Answer 2

A.

Explanation:

The answer is A. 2 seconds after it was shot.