Answer:
The balanced equation is:2Zn(s) + O2(g) → 2ZnO(s)
Step-by-step explanation:
From the balanced equation, we can see that 2 moles of zinc (Zn) react with 1 mole of oxygen (O2) to produce 2 moles of zinc oxide (ZnO).
To find the mass of product (ZnO) that can be prepared from 1.50 g of zinc (Zn), we can use the following steps:
Convert the given mass of zinc (Zn) to moles using its molar mass.
The molar mass of Zn is 65.38 g/mol.1.50 g Zn × (1 mol Zn / 65.38 g Zn) = 0.02296 mol Zn
Use the balanced equation to determine the number of moles of ZnO produced from the given amount of Zn.
From the balanced equation, we know that 2 moles of Zn produce 2 moles of ZnO, so:
0.02296 mol Zn × (2 mol ZnO / 2 mol Zn) = 0.02296 mol ZnO
Convert the moles of ZnO to its mass using its molar mass.
The molar mass of ZnO is
81.38 g/mol.0.02296 mol ZnO × (81.38 g ZnO / 1 mol ZnO) = 1.870 g ZnO
Therefore, 1.50 g of zinc can produce 1.870 g of zinc oxide.