22.0k views
4 votes
Given the balanced equation:

Calculate the mass of product that can be prepared from 1.50g of zinc metal.

2Zn(s)+O2(g)=2ZnO(s)

User Sactiw
by
7.7k points

1 Answer

6 votes

Answer:

The balanced equation is:2Zn(s) + O2(g) → 2ZnO(s)

Step-by-step explanation:

From the balanced equation, we can see that 2 moles of zinc (Zn) react with 1 mole of oxygen (O2) to produce 2 moles of zinc oxide (ZnO).

To find the mass of product (ZnO) that can be prepared from 1.50 g of zinc (Zn), we can use the following steps:

Convert the given mass of zinc (Zn) to moles using its molar mass.

The molar mass of Zn is 65.38 g/mol.1.50 g Zn × (1 mol Zn / 65.38 g Zn) = 0.02296 mol Zn

Use the balanced equation to determine the number of moles of ZnO produced from the given amount of Zn.

From the balanced equation, we know that 2 moles of Zn produce 2 moles of ZnO, so:

0.02296 mol Zn × (2 mol ZnO / 2 mol Zn) = 0.02296 mol ZnO

Convert the moles of ZnO to its mass using its molar mass.

The molar mass of ZnO is

81.38 g/mol.0.02296 mol ZnO × (81.38 g ZnO / 1 mol ZnO) = 1.870 g ZnO

Therefore, 1.50 g of zinc can produce 1.870 g of zinc oxide.

User ByteWalrus
by
8.1k points

Related questions