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2. How much heat does a 25.0 g ice cube absorb as its temperature increases from -20.4 °C to 0.00 °C? Specific heat of ice = 2.09 j/ g.C​

1 Answer

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Step-by-step explanation:

2.09 J/(g C) * 25 g * 20.4 C = ~1066 J

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