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Determine the number of calories required for 47.5g of Al to go from 25 to 62. The specific heat of Al is 0.900 J/g C.

User Gilad Hoch
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Answer: vvvv

Step-by-step explanation:

To calculate the amount of heat required to raise the temperature of a substance, we can use the following formula:

Q = m * c * ΔT

Where:

Q = the amount of heat required (in Joules)

m = the mass of the substance (in grams)

c = the specific heat of the substance (in J/g C)

ΔT = the change in temperature (in Celsius)

In this case, we want to find the amount of heat required to raise the temperature of 47.5g of Al from 25°C to 62°C, so:

m = 47.5g

c = 0.900 J/g C

ΔT = (62°C - 25°C) = 37°C

Plugging these values into the formula, we get:

Q = 47.5g * 0.900 J/g C * 37°C

Q = 1,321.25 Joules

Therefore, the number of calories required for 47.5g of Al to go from 25°C to 62°C is 315.50 calories, since there are 4.184 Joules in one calorie:

315.50 calories = 1,321.25 Joules / 4.184 Joules/calorie

User CmdrTallen
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