Question

Question 2

Complete the for loop and string method needed in this function so that a function call like "alpha_length("This has 1 number in it")" will return the output "17". This function should:

accept a string through the parameters of the function;

iterate over the characters in the string;

determine if each character is a letter (counting only alphabetic characters; numbers, punctuation, and spaces should be ignored);

increment the counter;

return the count of letters in the string.

def alpha_length(string):
character = ""
count_alpha = 0
# Complete the for loop sequence to iterate over "string".
for ___:
# Complete the if-statement using a string method.
if ___:
count_alpha += 1
return count_alpha

print(alpha_length("This has 1 number in it")) # Should print 17
print(alpha_length("Thisisallletters")) # Should print 16
print(alpha_length("This one has punctuation!")) # Should print 21

Answer 1

The completed function iterates over each character of a string, checks if the character is an alphabetic letter using the .isalpha() method, and returns the total count of such letters.

Step-by-step explanation:

The task is to complete a Python function that counts the number of alphabetic characters in a given string. The code should include a for loop to iterate through each character in the string and an if statement to check whether a character is an alphabetic letter using the .isalpha() method. Here is the completed function:

def alpha_length(string):
count_alpha = 0
for character in string:
if character.isalpha():
count_alpha += 1
return count_alpha
When called with different strings, such as "This has 1 number in it", "Thisisallletters", or "This one has punctuation!", the function will return the count of letters in each string, ignoring numbers, spaces, and punctuation.